Torpedo Bats and the Physics of the Sweet Spot

What will happen on the stick if the ball hit the stick and bounce back? If you said the stick will turn right then it’s right. We can think of this as a collision. When two facilities collide, they make forces to each other. And in a new type, forces are equal and vice versa protecting the total speed of the ball-bat system. We define the acceleration as the product of a mass and speed of an object.

Since the ball leaves back, the only way to a protected speed is the retreat of the stick. (I know that this thinking of my experience will make a handsome heel for the spectator sports, but it will help us to understand what happened at a sweet point.

Clash outside the center

Ok, pick up the stick and bring it back to the starting position. The ball started again to the stick. However, this time, instead of the middle, it is directed to the end. Like this:

The stick is still back to the right but now cheat About the center, isn’t it? Why does this happen? Well, the momentum is still protected, but now there is an acceleration related to another protected amount. The angle is an open momentum, except for an emergency, instead of a rotation movement instead of a flat move.

Linear speed depends on the mass and speed of the facility, equivalent to the angle speed and the product of the moment of inertia. Inertia is like a rotating mass of the moment – it depends not only from the object of the object, but how the crowd depends on the distribution of. Thus, after the rod then retreated from the ball shot, it has a rotating angle speed.

So what will happen before collision? Wand rotates and no angular momentum so it is so protected by angle speed ball must have angle speed. Yes, it may have an angle speed even if a mass is not turned. (This is one of the moments of physics only looked strange.) Bucu of the ball depends on the momentum and where the stick is hit.